Perimeter of isoceles triangle is 24cm. Sides 'x' = x + 3, side 'y' = x + 2, calculate the area

Area isosceles = hb/2 = hy/2Perimeter = 24x+3+x+3+x+2 = 243x + 8 = 243x = 16x = 16/3h^2 = (x+3)^2 - ((x+2)/2)^2h^2 = 56h = 2 root14area = 2root14*(x+2)/2area = 13.719 to 1dp

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Answered by Charlie B. Maths tutor

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