Find the intergal of 2x^5 -1/(4x^3) -5 giving each term in its simplest form.

When integrating, we raise the power by 1 and divide by the new powerSo, 2x⁵ becomes 2x⁶ /6 which simplified down as the question asks is x^6/3-1/(4x³) is -(1/4)x^^-3 using indices laws, raising the power by one and dividing by the new power gives -(1/4)x^-2/(-2) which simplifies down to (1/8)x^-2-5 becomes -5xDon't forget when intgrating to add the constant, so putting all this togehter gives us:x⁶/3 +(1/8)x^-2-5x+c