Find the intergal of 2x^5 -1/(4x^3) -5 giving each term in its simplest form.

When integrating, we raise the power by 1 and divide by the new powerSo, 2x5 becomes 2x6 /6 which simplified down as the question asks is x^6/3-1/(4x3) is -(1/4)x^-3 using indices laws, raising the power by one and dividing by the new power gives -(1/4)x-2/(-2) which simplifies down to (1/8)x-2-5 becomes -5xDon't forget when intgrating to add the constant, so putting all this togehter gives us:x6/3 +(1/8)x-2-5x+c

EW
Answered by Emily W. Maths tutor

3377 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I find the integral ∫(ln(x))^2dx ?


Differentiate f(x)=(x+sin(2x))^4


Differentiate y=(5x^4)cos(2x)


For sketching the graph of the modulus of f(x) (in graph transformations), why do we reflect in the x-axis anything that is below it?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning