Find the intergal of 2x^5 -1/(4x^3) -5 giving each term in its simplest form.

When integrating, we raise the power by 1 and divide by the new powerSo, 2x5 becomes 2x6 /6 which simplified down as the question asks is x^6/3-1/(4x3) is -(1/4)x^-3 using indices laws, raising the power by one and dividing by the new power gives -(1/4)x-2/(-2) which simplifies down to (1/8)x-2-5 becomes -5xDon't forget when intgrating to add the constant, so putting all this togehter gives us:x6/3 +(1/8)x-2-5x+c

EW
Answered by Emily W. Maths tutor

3222 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the coordinates of the stationary point of y = x^2 + x - 2


How do you factorise quadratic, cubic functions or even quartic functions?


Evaluate the integral of cos(x)sin(x)(1+ sin(x))^3 with respect to x.


How many roots does the equation x^2 = x + 12 have and what are they?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning