Find the intergal of 2x^5 -1/(4x^3) -5 giving each term in its simplest form.
When integrating, we raise the power by 1 and divide by the new powerSo, 2x5 becomes 2x6 /6 which simplified down as the question asks is x^6/3-1/(4x3) is -(1/4)x^-3 using indices laws, raising the power by one and dividing by the new power gives -(1/4)x-2/(-2) which simplifies down to (1/8)x-2-5 becomes -5xDon't forget when intgrating to add the constant, so putting all this togehter gives us:x6/3 +(1/8)x-2-5x+c
EW
Related Maths A Level answers
All answers ▸Solving a quadratic with ax^2 e.g. 2x^2 - 11x + 12 = 0
Solve these simultaneous equations: 2x+y-5=0 and x^2-y^2=3
Find the gradient of the curve y = x^2(ln(x)) at x = e
let line L have the equation 4y -3x =10, and line M passes through the points (5,-1) and (-1,8), find out if they are perpendicular, parallel, or neither