Find the general solution of the equation tan(2x + pi/2) = SQRT(3), giving your answer for x in terms of π in a simplified form.

Assume y = 2x + pi/2,
Since the period of 'tangent' is pi, the general solution of 'y' to valid the equation of tan(y) = SQRT(3) is the form of y = npi+pi/3 where 'n' is any positive or negative integer and zero.
Substitute y back to the equation, it becomes 2x + pi/2 = n
pi+pi/3.
Simplify this equation in the form of 'x', it becomes: x = 1/2(n*pi - pi/6) where 'n' is any positive or negative integer and zero.

CH
Answered by Chunlong H. Maths tutor

4212 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I calculate the rate of change of something for which I don't have an equation?


What is the centre and radius of the circle x^2+y^2-6x+4y=-4


Line AB has equation 4x+5y+2=0. If the point P=(p, p+5) lies on AB, find P . The point A has coordinates (1, 2). The point C(5, k) is such that AC is perpendicular to AB. Find the value of k.


Using substitution, integrate x(2 + x))^1/2 where u^2 = 2 + x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning