Find the general solution of the equation tan(2x + pi/2) = SQRT(3), giving your answer for x in terms of π in a simplified form.

Assume y = 2x + pi/2,
Since the period of 'tangent' is pi, the general solution of 'y' to valid the equation of tan(y) = SQRT(3) is the form of y = npi+pi/3 where 'n' is any positive or negative integer and zero.
Substitute y back to the equation, it becomes 2x + pi/2 = n
pi+pi/3.
Simplify this equation in the form of 'x', it becomes: x = 1/2(n*pi - pi/6) where 'n' is any positive or negative integer and zero.

Answered by Chunlong H. Maths tutor

3058 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve the inequality x^2 > 3(x + 6)


How many ways are there to arrange n distinct objects in a CIRCLE?


Express the fraction (p+q)/(p-q) in the form m+n√2, where p=3-2√2 and q=2-√2.


The line L1 has vector equation,  L1 = (  6, 1 ,-1  ) + λ ( 2, 1, 0). The line L2 passes through the points (2, 3, −1) and (4, −1, 1). i) find vector equation of L2 ii)show L2 and L1 are perpendicular.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy