A) Differentiate ln(x) b) integrate ln(x)

A) y=ln(x) Ey = x Ey(dy/dx ) = 1 Eln(x)(dy/dx) = 1 X(dy/dx) = 1 Dy/dx = 1/xb) y = 1 * ln(x) V = ln(x) U= x dv/dx =1/x Du/dx = 1xln(x) - (integral) x * (1/x)xln(x) - (integral) 1= xln(x) -x + C

SR
Answered by Stanley R. Maths tutor

3613 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The gradient of a curve is given by dy/dx = 6sqrt(x) + 2. The curve passes through the point (16, 38). Find the equation of the curve.


Please explain Pythgoras Theorem


Find the intergral of 2x^5 - 1/4x^3 - 5 with respect to x.


Differentiate x^3 − 3x^2 − 9x. Hence find the x-coordinates of the stationary points on the curve y = x^3 − 3x^2 − 9x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning