Solve the simultaneous equations: 3x + y = 19 and x - 2y = -3

First rearrange x - 2y = -3 by adding 2y to each side to give x = -3 + 2ySubstitute this into the first eq. to give 3(-3 +2y) + y = 19Expand brackets first: -9 + 6y + y = 19Rearrange and simplify by collecting the y terms and adding 9 to both sides, so terms of y are on one side and numbers on the other: 7y = 28Divide both sides by 7 to get y = 28/7 = 4Substitute y = 4 into the equation for x to find the value of x: x = -3 + 2y = -3 + (2*4) = -3 + 8 = 5x=5, y = 4

JM
Answered by Jessica M. Maths tutor

5145 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A line has equation y=3x+4, state the gradient and the y-intercept


a right-angled triangle has base 2x + 1, height h and hypotenuse 3x. show that h^2 = 5x^2 - 4x - 1


Factorise and solve x^2-8x+15=0


How do you solve the simultaneous equations x^2+y=1 and -x+y=-1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning