What is the equation of the tangent to the curve y=x^3+3x^2+2 when x=2

dy/dx=3x^2+6xx=2m=3(2)^2+6(2)=24at x=2 y=22(2,22)y-22=24(x-2)y-22=24x-48y=24x-26

KH
Answered by Kieran H. Maths tutor

4051 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the integral of a^(x) where a is a constant


Calculate the value of the definite integral (x^3 + 3x + 2) with limits x=2 and x=1


How do we integrate x^2?


Find the binomial expansion of (2+x)^3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning