What is the equation of the tangent to the curve y=x^3+3x^2+2 when x=2
dy/dx=3x^2+6xx=2m=3(2)^2+6(2)=24at x=2 y=22(2,22)y-22=24(x-2)y-22=24x-48y=24x-26
KH
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