equation(1) h = 3t^2 a) find h when t=5 b)find t when h=108

for part AYou would but the t² into brackets , then substitute t=5 to get h=3(5²) using BIDMAS do the 5² = 25 so that h=3(25) so you end up with h=75
for part B first you would rearrange the equation to make t the subject (t on its own on one side) h/3=t² then square root h/3sqrt{h/3}=t Then finally you substitute In h=108 sqrt{108/3}=tsqrt(3)=t