Solve the simultaneous equations: x^2+y^2=36 ; x=2y+6

Substitute x in terms of y into the first equation:

(2y+6)2+y2=36

Use FOIL to expand the brackets

4y2+24y+36+y2=36  =>   5y2+24y=0

y(5y+24)=0  =>  y=0   or    y=(-24)/5

Substitute these values of y into the second equation to find x

when y=0, x=2*0+6  =>  x=6

when y=(-24)/5,  x=2*(-24)/5+6  =>  x=-3.6

DB
Answered by Daniel B. Maths tutor

30331 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 3x - 5 = 13


What is the definition of the slope?


Solve the simultaneous equations, 3x + y = 10 and x + y = 4.


Expand the following : (2x+3)(x-1)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences