y = p x q^(x - 1), When x = 1, y = 10, and when x = 6, y = 0.3125. Find the value of 'y' when x = 3
When x = 1, y = 10Therefore, p x q(1 - 1) = 10 p x q0 = 10 p x 1 = 10, p = 10When x = 6, y = 0.3125 p x q(6 - 1)= 0.3125 10 x q5 = 0.3125 q5 = 0.03125, q = (0.03125)1/5, q = 0.5Let x = 3, 10 x 0.5(3 - 1) = y, y = 2.5
PM
Related Maths GCSE answers
All answers ▸A bag contains 8 oranges, 9 pears and 13 apples. What is the probability a pear is picked?
What is the product of prime factors of 270?
how do you solve a linear equation where there are unknowns on each side e.g. 4(k + 7) = 12k + 4
The number of uniform spherical balls that can be produced from a given mass of lead is inversely proportional to the radius of the ball cubed. If 2744 balls can be made when the radius is 1mm, how many balls can be made when the radius is 1.4mm ?