y = p x q^(x - 1), When x = 1, y = 10, and when x = 6, y = 0.3125. Find the value of 'y' when x = 3
When x = 1, y = 10Therefore, p x q(1 - 1) = 10 p x q0 = 10 p x 1 = 10, p = 10When x = 6, y = 0.3125 p x q(6 - 1)= 0.3125 10 x q5 = 0.3125 q5 = 0.03125, q = (0.03125)1/5, q = 0.5Let x = 3, 10 x 0.5(3 - 1) = y, y = 2.5
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