Given the curve y=x^2 -6x +8, find the turning point.

For a turning point, the differential of the curve is equal to 0. Therefore dy/dx = (12)x^(2-1) - (61)x^(1-1) + 0 = 0. This gives x = 3. Substitute this back into the original equation to get y=-1. Therefore the turning point is at (3, -1).

EB
Answered by Ellis B. Maths tutor

6719 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The point P has coordinates (4, 5). The point Q has coordinates (a, b). A line perpendicular to PQ is given by the equation 5x+3y=11. Find an expression for b in terms of a.


How do I factorise a quadratic equation?


v^2=u^2 + 2as u=12 a=-3 s = 18 Find v


How to factorise a quadratic


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning