if f(x) = 4x^2 - 16ln(x-1) - 10, find f'(x) and hence solve the equation f'(x)=0.

f(x) = 4x2 - 16ln(x-1) -10, f'(x) = 8x - 16/(x-1), so if f'(x)=0, then 8x - 16/(x -1)=0, 8x(x-1) - 16 = 0, 8x2- 8x - 16 =0, 8(x2- x - 2) = 0, x2 - x - 2 = 0, (x - 2)(x + 1) =0, so x = 2 and x = -1

EB
Answered by Ellie B. Maths tutor

3177 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate y=(x^2+5)^7


Find the area between the curve y = 8 + 2x - x^2 and the line y = 8 - 2x.


Find dy/dx at t=3, where x=t^3-5t^2+5t and y=2t^2


How do you find the stationary points on a curve?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences