if f(x) = 4x^2 - 16ln(x-1) - 10, find f'(x) and hence solve the equation f'(x)=0.

f(x) = 4x2 - 16ln(x-1) -10, f'(x) = 8x - 16/(x-1), so if f'(x)=0, then 8x - 16/(x -1)=0, 8x(x-1) - 16 = 0, 8x2- 8x - 16 =0, 8(x2- x - 2) = 0, x2 - x - 2 = 0, (x - 2)(x + 1) =0, so x = 2 and x = -1

EB
Answered by Ellie B. Maths tutor

3288 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Express (16x+78)/(2x^2+25x+63) as two fractions


Explain the basics of projectile motion


Integrate tan(x)^2 with respect to x


Prove that n is a prime number greater than 5 then n^4 has final digit 1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences