Find minimum and maximum of x^2+1 if they exist

There are several methods of finding the extrema(plural of extremums or in other words minimum or maximum values) of a function.

For now we will analyse the function using the dy/dx of f(x)=y=x+1, f`(x) = 2x
The sign of the diferentiation of the function change at x=0. Therefore for x<0 dy/dx<0 and the function is declining. For x>0 dy/dx>0 and the function is uprising. We can conclude that there is a minimum at x=0. We cannot find a maximum of the function as it approaches infinity.
 

Answered by Pavel G. Maths tutor

3420 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that y= 1/ (6x-3)^0.5 find the value of dy/dx at (2;1/3)


Given that y =2x^3 + 3/(x^2), find a) dy/dx and b) the integral of y


Differentiate f(x) = (3x + 5)(4x - 7)


Solve the following equations. Leave answers in simplest terms a)e^(3x-9)=8. b) ln(2y+5)=2+ln(4-y)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy