Solve the inequality x^2 - 9 > 0

This is a quadratic inequality, because we have an x2 term, so we answer this question by examining the graph of the associated equation y = x2 - 9, and then find out where this graph is greater than 0.So first, we find where the equation, y = x2 - 9 is equal to zero (i.e. y = 0). This is simply solving a quadratic, which we do by factorising and equating each term in brackets to zero, i.e.:x2 - 9 = 0This is the difference of two squares, so the factorisation should be relatively familiar.(x+3)(x-3) = 0Therefore x= - 3 or x = 3.This tells us that the graph crosses the x-axis at x=3 and x=-3.Then, we need to consider what the rest of the graph looks like. Since the equation y = x2 - 9 has a positive x2 term, this graph must be a positive parabola (U-shape) graph. Putting this all together we can sketch a graph of the equation, and now we look back to our original inequality, which asks for when this graph (when the y-values) are greater than zero. We can see this happens when either x > 3 or when x< -3 and so this is our solution.

RH
Answered by Rose H. Maths tutor

16220 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you differentiate (2x+xe^6x)/(9x-(2x^2)-ln(x)) w.r.t. x?


Using the substitution of u=6x+5 find the value of the area under the curve f(x)=(2x-3)(6x+%)^1/2 bounded between x=1 and x=1/2 to 4 decimal places.


How would you solve the inequality x^2-2x-8 >= 0?


Solving harder exponential equations, e.g. 5/[exp(x) + 6exp(-x)] - 1 = 0 . CORE MATHS.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning