An industrial process converts the alkene ethene into ethanol, according to the following reaction: C2H4 + H2O --> CH3CH20H. What mass of ethanol can be made from 53g of ethane, given that the water is in excess. (2 marks) (6-7 grade)

This question is all about using the mols equation question (mols = mass/molecular weight).
It's best to break it down into steps:
1) calculate the molecular masses of the compounds that are involved in the question (ignore the H20 as this is in excess):
C2H4 = 28 CH3CH2OH = 46
2) calculate the mols of ethene:
mols = mass/molecular weight
C2H4 = 53/28 = 1.89 (2dp)
As the number of number of ethanols produced in the equation is equal to the number of ethenes, the mols of ethanol created is equal to the mols of ethene used. This means the mols of ethanol created is 1.89.
3) Now you need to use the same equation to calculate the mass of ethanol created.
mols = mass/molecular weight therefore mass = mols x molecular weight
mass ethanol = 1.89 x 46 = 87g