Given that A(sin θ + cos θ) + B(cos θ − sin θ) ≡ 4 sin θ, find the values of the constants A and B.
Since this must be true for all values of θ, and cos and sin are distinct functions, no non-zero multiple of cosθ could ever be equal to 4 sinθ for all values of θ. Therefore, the overall multiple of cosθ on the left-hand-side must be 0.
Therefore, Acosθ + Bcosθ ≡ 0and (A+B) cosθ ≡ 0so A = - B
We can then plug this back into the equation to solve for A:A(sinθ + cosθ) - A(cosθ - sinθ) ≡ 4sinθAsinθ - (-Asinθ) = 4sinθ [the cosθ terms cancel one another out]Asinθ + Asinθ = 4sinθ2A = 4A = 2B = - A = - 2
DB
Related Maths A Level answers
All answers ▸Can you prove to me why cos^2(X) + sin^2(X) = 1?
How can I find the derivative of y = tan(x)?
The graphs of functions f(x)=e^x and h(x)=e^(-.5x), where x is a real number and 0<x<1 ,lie on a plane. Draw these functions and find the area they and the line x=0.6 enclose using integration correct to 3 decimal places
use the substitution u=2+ln(x) to show that int(e,1(ln(x)/x(2+ln(x)^2))dx)=p+ln(q) , where p and q are rational numbers.