Solve the equation 3x^2+2x-3=3.
- rearrange the formula so that it is equal to zero by subtracting 3 from both sides of the equation.3x2+2x-6=02) To check if this formula can be factorised you can check if the value of b2-4ac for this formula is equal to a square number. If not you must use the quadratic formula.ax2+bx+c = 3x2+2x-6where a= 3, b= 2 and c=-6so b2-4ac = (2)2-4(3)(-6)= 76 which is not a square number 3) therefore sub it into the quadratic formula using the values of a,b and c as above where a= 3, b= 2 and c=-6 and find 2 different answers to the equation in the question. where x= 1.11 or -1.79 to 3 s.f
JB
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