Solve simultaneously. x^2+y^2 = 25 ; y - 3x = 13

y = 3x + 1310x^2 + 78x + 169 = 2510x^2 +78x +144 = 0(5x+24)(2x+6) = 0x = -24/5 or -3y = -7/5 or 16

BH
Answered by Ben H. Maths tutor

2485 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

simplify fully (x^2-5x+4)/(x^2-2x-8)


Given the two equations [1](3x + 4y = 23) and [2](2x + 3y = 16), find the values of x and y


Simplify √(4x^8).


State the nth term of the following sequence: 3,7,11,15,19...


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences