Solve the inequality x^2 – 5x – 14 > 0.

In order to solve this, the quadratic must be factorised. This means we're trying to get the equation into the form (x+a)(x+b)>0 where a and b are constants where a x b = -14 and a + b = -5. This turns out to be -7 and 2. These constants show us where the graph crosses the axis. We currently have the equation y = (x-7)(x+2) and are looking for solutions when y>0. This means on the graph it will be above the x-axis, i.e. x > 2 and x < -7.

MP

Related Maths A Level answers

All answers ▸

What is Differentiation?


(19x - 2)/((5 - x)(1 + 6x)) can be expressed as A/(5-x) + B/(1+6x) where A and B are integers. Find A and B


Why do I need to add the + C when finding an indefinite integral?


Find the coordinates of the sationary points on the curve x^2 -xy+y^2=12