What is the gradient of this curve y=5x^3+6x^2+7x+8 at point x=3?
When differentiating an equation (y) you find the equation of the gradient, called dy/dx. The rule for differentiating a power of x is given below:y=x^n dy/dx= nx^(n-1)Applying this rule to this question you get dy/dx=15x^2+12x+7, this is the equation of the gradient. To find the gradient at x=3, substitute x=3 into dy/dx. This gives the gradient (dy/dx) as 178.
TD
Related Maths A Level answers
All answers ▸Sketch the curve y = (2x-1)/(x+1) stating the equations of any asymptotes and coordinates of the intersection with the axis. As an extension, what standard transformations from C1 could you use on y=1/x to get this curve?
Find values of y such that: log2(11y–3)–log2(3) –2log2(y) = 1
integrate (2x^4 - 4/sqrt(x) + 3)dx
Solve the following equation: x^(3) - 6x^(2) + 11x - 6 = 0