y=e^2x-11e^x+24 Find the stationary point, nature of the stationary point, the x-intercepts and the y-intercept (calculator allowed)

Stationary point:
dy/dx = 2e^2x - 11e^x =0
2e^2x = 11e^x
e^x=5.5 (can divide by e^x since e^x > 0 for all x)
x=ln(5.5), y=5.5^2-115.5+24=-6.25
Answer: (ln(5.5),-6.25)
Nature of stationary point:
Evaluate y'' at x=ln(5.5)
y''= 4e^2x-11e^x = 4
5.5^2-11*5.5 = 60.5
Since y''>0, local minima
x-intercept:
Set y=0
y=(e^x-3)(e^x-8)=0
e^x=3 or e^x=8
x=ln(3) and x=ln(8)=3ln(2)
Answers: (ln(3),0) and (3ln(2),0)
y-intercept:
Set x=0
y=1-11+24=14
y-intercept: (0,14)

AJ
Answered by Asmita J. Maths tutor

3026 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given f(x) = 7(e^2x) * (sin(3x)), find f'(x)


What is a derivative and how do we calculate it from first principles?


A curve has equation y = f(x) and passes through the point (4, 22). Given that f ′(x) = 3x^2 – 3x^(1/2) – 7, use integration to find f(x), giving each term in its simplest form.


If y = 5x^3 - 2x^2 + 2, what is dy/dx?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning