Solve the following simultaneous equation: y= x^2 - 3x + 4 y - x = 1

When it comes to solving simultaneous equations the way you structure your working out will really help you get to the correct answer. The layout can be used for all simultaneous equations and will make even the more complicated ones seem a lot less daunting. Firstly label the two equations: y= x2 - 3x + 4  (1) and y - x = 1 (2). Substitute (1) into (2). x2 - 3x + 4 - x = 1 This equation becomes (3). Solve (3) by putting all the terms onto one side making sure x2 stays positive to simplify. x2 - 4x + 3 = 0. Now factorise the equation(x-3)(x-1) = 0. Either x - 3 = 0 or x-1=0, therefore x = 3 or x = 1. Now substitute each possible answer into the simplest simultaneous equation which would be (2) to solve for y. When x = 3 y - 3 = 1 y = 4 When x = 1 y - 1 = 1 y = 2.

AP
Answered by Anisha P. Maths tutor

6942 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are 12 counters in a bag. There is an equal number of red counters, yellow counters and blue counters in the bag. There are no other counters in the bag. 3 counters are taken from the bag. Work out the probability of taking 3 red counters.


Differentiate: 6x^2 + 5x +7 =y


write (x+2)(x+3)(x+5) in the form ax^3+bx^2+cx+d


Matt had 3 piles of coins, A, B and C. Altogether there was 72p. Pile B had twice as much as pile A. Pile C had three times as much as pile B.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning