Solve simultaneously x + y = 1, 2x + 3y =9

To solve this problem I would begin by rearranging the first equation to equal X.1) x + y = 1 -> x = 1 - yI would then substitute this into the second equation.2) 2x + 3y = 9 -> 2(1-y) + 3y = 9Then multiply out the bracket.3) 2(1-y) + 3y = 9 -> 2 - 2y + 3y = 9Simplify.4) 2 - 2y + 3y = 9 -> 2 + y = 9Solve. 5) 2 + y = 9 -> y = 7resubstitute this into the first equation and solve.6) x + y = 1 -> x + 7 = 1 -> x = -6which gives you the final solution of X = -6 and y = 7.

Answered by Isabel C. Maths tutor

2235 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are 420 balls in a ball pool. There is a combination of violet, blue, yellow and green balls. 2/7 are violet, 35% are blue and the ratio of yellow to green is 4:5. How many of each colour ball is there in the ball pool?


Factorise x^2 +6x + 8


Solve the Simultaneous equation: 6x+3y=13, 14x-9y=9?


Solve the equation: x^2 - 9x + 20 = 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy