Find the roots for the quadratic equation x^2 +2x-3 = 0
I would show the student two methods of solving this answer.The first method by:Finding two numbers that multiply to make -3 and simultaneously add to make +2.The two numbers that satisfy this is +3 and -1. We then put these into brackets accompanied by the x term, like so: (x+3)(x-1) = 0Then, to find the solutions: x+3=0 therefore x=-3And solution number 2: x-1=0 therefore x=+1Alternatively, we could use the quadratic formula to work the values of x like so:x=-b+/-√ b^2-4ac 2aFamiliarize ourselves that our equation is in this format: ax^2 +bx+c Pop in the values of our formula where a=1 b=2 and c=-3And we get two answers, x=-3 and x=+1
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