Differentiate y=ln(x)+5x^2, and give the equation of the tangent at the point x=1

First differentiate the equation, giving you, y'=(1/x)+10x. To get the gradient at this point of the curve, plug in x=1, to get a y' value of 11, and a y value of 5. From there you can plug these three numbers into the equation y-y1=y'(x-x1) to get the equation for the straight line y=11x-6.

HM
Answered by Harrison M. Maths tutor

3122 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I do definite integrals?


What is the indefinite integral of cos^2x?


Core 3 Differentiation: If y = (3x^2 + 2x + 5)^10, find its derivative, dy/dx. Hint: Use the chain rule.


Using Trigonometric Identities prove that [(tan^2x)(cosecx)]/sinx=sec^2x


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences