solve the simultaneous equation: 8x+2y=46; 7x+3y=47

To solve this problem, we want to make either the x or the y values either equation the same.To work out whether to change the x or the y values, work out the lowest common multiple for each.For x, the values are 7 and 8 so the lowest common multiple is 56For y, the values are 2 and 3 so the lowest common multiple is 6 - this is lower hence we will change the y valuesto get 6y in each equation, multiply the first by 3 (as 2y x 3 = 6y) and the second by 2 (as 3y x 2 = 6y)This will give:24x+6y=13814x+6y=94minusing the bottom equation from the top one will eliminate the y values and give:10x = 44therefore dividing by 10:x=4.4

JW
Answered by Jess W. Maths tutor

4961 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

a=7 and b=2, Work out the value of (a/b)-a^b


Solve the equation x^{2}-2x-15 = 0


Simplify fully: (24 - √ 300)/(4√ 3 - 5). Give your answer in the form a√ b where a and b are integers and find the values of a and b.


What is the nth-term of this sequence? 29, 26, 23, 20, 17...


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning