Integrate (x^2 +2)(2x-6) with respect to x.

For a simple integration like this, begin by expanding the brackets to get 2x3-6x2+4x-12. Next each term should be integrated with respect to x, begin with the first term, each peer should be raised by 1, and then the whole term should be divided by the new power. eg. 2x3 ->2x4 and is then divided by its new power, to become 2x4/4 which simplifies to x4/2. This is continued for each term. Remember that -12 can be though of as -12x0 and therefore this will become -12x. Finally a constant must be added to the end of the solution as it is unknown what term could be lost when differentiating, it is common practice to use +C or +k. When all the terms are found, they are added together to get the solution which is, x4/2 -2x3+ 2x2-12x + C.

NB
Answered by Nicholas B. Maths tutor

2992 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

I'm trying to integrate f(x)=sin(x) between 0 and 2 pi to find the area between the graph and the axis but I keep getting 0, why?


write 2(sin^2(x)- cos^2(x)) + 6 sin(x) cos(x) in terms of cos(2x) and sin(2x)


Express 3cos(theta) + 5sin(theta) in the form Rcos(theta - alpha) where R and alpha are constants, R>0 and 0<alpha<90. Give the exact value of R and the value of alpha to 2dp.


How would you sketch the curve of a graph?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences