A curve has the equation: x^3 - x - y^3 - 20 = 0. Find dy/dx in terms of x and y.

x3 - x - y3 - 20 = 0 Find dy/dx. Differentiate with respect to x.
3x2 - 1 - 3y2(dy/dx) = 0Therefore: dy/dx = (3x2 - 1)/3y2

KP
Answered by Karishma P. Maths tutor

3191 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find ∫(x^3+x^2+6)dx.


A curve has equation x = (y+5)ln(2y-7); (i) Find dx/dy in terms of y; (ii) Find the gradient of the curve where it crosses the y-axis.


Differentiate y = (6x-13)^3 with respect to x


The function f has domain (-∞, 0) and is defines as f(x) = (x^2 + 2)/(x^2 + 5) (here ^ is used to represent a power). Show that f'(x) < 0. What is the range of f?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences