A curve has the equation: x^3 - x - y^3 - 20 = 0. Find dy/dx in terms of x and y.

x3 - x - y3 - 20 = 0 Find dy/dx. Differentiate with respect to x.
3x2 - 1 - 3y2(dy/dx) = 0Therefore: dy/dx = (3x2 - 1)/3y2

KP

Related Maths A Level answers

All answers ▸

Find the area under the curve y = (4x^3) + (9x^2) - 2x + 7 between x=0 and x=2


Earth is being added to a pile so that, when the height of the pile is h metres, its volume is V cubic metres, where V = (h6 + 16) 1 2 − 4.Find the value of dV/dh when h = 2.


Solve the equation cosec^2(x) = 1 + 2cot(x), for -180° < x ≤ 180°.


The points A and B have coordinates (2,4,1) and (3,2,-1) respectively. The point C is such that OC = 2OB, where O is the origin. Find the distance between A and C.