Find the coordinate of the stationary point on the curve y = 2x^2 + 4x - 5.
The important point in the question is the term 'stationary point'. This is where the graph of y will 'flattern out'. If we look at this graph, we can say that the gradient is equal to 0 at this point. Therefore, dy/dx = 0. dy/dx = 4x +4 = 0. Therefore, x = -1. Plug this value back into y to get y = 2(-1)^2 + 4(-1) - 5 = -7. So the coordinate of the stationary point will be at (-1,-7).
SM
Related Maths A Level answers
All answers ▸(C3 question). Find an expression for all stationary points on the curve y=sin(x)cos(x). How many such points are there and why?
Differentiate: f(x)=2(sin(2x))^2 with respect to x, and evaluate as a single trigonometric function.
Given that y = x^4 + x^(1/3) + 3, find dy/dx
Differentiate y=e^(x)*sin(x) with respect to x