Express (4x)/(x^2-9) - (2)/(x+3) as a single fraction in its simplest form.

First we must expand the demoninator to; (x+3)(x-3)Then we can multiply the left hand fraction on top and bottom by (x-3) to get a common demoninatorthis gives us; (4x)/((x+3)(x-3)) - ((2)(x-3))/((x+3)(x-3))simplyfy the top to get; (2x+6)/((x+3)(x-3))the numerator then can be expanded to give; (2(x+3))/((x+3)(x-3))The (x+3) cancels on top and bottom to give us the final answer; 2/(x-3)

EE

Related Maths A Level answers

All answers ▸

The function f is defined for all real values of x as f(x) = c + 8x - x^2, where c is a constant. Given that the range of f is f(x) <= 19, find the value of c. Given instead that ff(2) = 8, find the possible values of c.


Find the radius and centre of the circle given x^2+4x+y^2+2y=20


y=4x^3+6x+3 so find dy/dx and d^2y/dx^2


solve x^3+2x^2+x=0