Given two functions x = at^3 and y = 4a, find dy/dx

Solution: Parametric Differentiation with utilisation of Chain Rule.
By the chain rule: dy/dx = dy/dt * dt/dx
Note: dt/dx = 1 / (dx/dt)
So dy/dt = 0, dx/dt = 3at^2
So dy/dx = 0 * 1/(3at^2) and hence dy/dx = 0.

MP
Answered by Michele P. Maths tutor

3388 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How to factorise any quadratic expression


How can the y=sin(x) graph be manipulated?


Integrate the function f(x) = 1/(4x-1)


Use implicit differentiation to find dy/dx of the equation 3y^2 + 2^x + 9xy = sin(y).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences