Given two functions x = at^3 and y = 4a, find dy/dx

Solution: Parametric Differentiation with utilisation of Chain Rule.
By the chain rule: dy/dx = dy/dt * dt/dx
Note: dt/dx = 1 / (dx/dt)
So dy/dt = 0, dx/dt = 3at^2
So dy/dx = 0 * 1/(3at^2) and hence dy/dx = 0.

MP
Answered by Michele P. Maths tutor

3413 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

integrate ln(x) using integration by parts


Express the polynomial x^3+x^2-14x-24 as a product of three linear factors.


Using the trigonometric identity for tan(A + B), prove that tan(3x)=(3tan(x)-tan^3(x))/(1-3tan^2(x))


Rationalise the complex fraction: (8 + 6i)/(6 - 2i)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences