Given two functions x = at^3 and y = 4a, find dy/dx

Solution: Parametric Differentiation with utilisation of Chain Rule.
By the chain rule: dy/dx = dy/dt * dt/dx
Note: dt/dx = 1 / (dx/dt)
So dy/dt = 0, dx/dt = 3at^2
So dy/dx = 0 * 1/(3at^2) and hence dy/dx = 0.

MP
Answered by Michele P. Maths tutor

3801 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I integrate by parts?


Differentiate sin3x-3x= f(x)


Find the binomial expansion of ((x^2) − 5)^3


If (x+1) is a factor of 2x^3+21x^2+54x+35, fully factorise 2x^3+21x^2+54x+35


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning