Solve the simultaneous equations: 2x+5y=25, x=y+2

using our second equation, we can see that x=y+2. Therefore we can sub x into the first equation. This will give us 2*(y+2)+5y=25. We can go ahead and expand the brackets, which gives us 2y+4+5y=25. We can combine the y terms which gives 7y+4=25. We can take 4 away from both sides with gives 7y=21, and divide both sides by 7 so y=3. We can sub 3 into y in the original equation, to give that x=5.

LW

Related Maths GCSE answers

All answers ▸

Find the exact length of side A in the triangle and give you answer in the simplest form. (It is a right angled triangle. Side C is (6+√(3)) and side B is (3 + 2√(3)).


How do you know which circle theorems to use when answering a question?


Expand and simplify 4x(x+3) - (2x-3)2


Rearranging equations