Balance the equation for the reaction of sodium hydroxide with sulphuric acid.

H2SO4 + NaOH --> Na2SO4 + H2OWrite out all the elements involved, and how many times they appear on each side.H 3:2,S 1:1,O 5:5,Na 1:2.Start by making the number of sodiums the same on both sides by putting a 2 in front of NaOH:H2SO4 + 2NaOH --> Na2SO4 + H2O.H 4:2,S 1:1,O 6:5,Na 2:2.Then make the number of hydrogens equal on both sides by putting a 2 in front of H2O:H2SO4 + 2NaOH --> Na2SO4 + 2H2O.This makes the number of oxygens equal as well, so the equation has now been balanced.

LB
Answered by Louise B. Chemistry tutor

13651 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

What is the difference between an ionic bond and a covalent bond?


Describe and explain how changes in the earth atmosphere, from the Precambrian Era (where the earth as occupied by volcanoes), have changed to form the surface of the Earth today and its atmosphere.


Why can crude oil be separated by fractional distillation?


When do halogens displace each other in solutions of their salts?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning