Differentiate y= (3x^2+2x-6)^8

This is an example of where we must use the chain rule:
Firstly as with simpler differentiation we multiply the function by the power then subtract 1 from the power to get:
8(3x^2+2x-6)^7
Then we must also multiply this by the differential of the function in the bracket which is 6x+2, to get:
dy/dx = 8(6x+2)(3x^2+2x-6)

OT
Answered by Ollie T. Maths tutor

3650 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Prove the identity: (cos θ + sin θ)/(cosθ-sinθ) ≡ sec 2θ + tan 2θ


4. The curve C has equation 4x^2 – y3 – 4xy + 2y = 0. P has coordinates (–2, 4) lies on C. (a) Find the exact value of d d y x at the point P. (6) The normal to C at P meets the y-axis at the point A. (b) Find the y coordinate of A


Why does differentiation give us the results that it does?


Use the substitution u = 6 - x^2 to find the value of the integral of (x^3)/(sqrt(6-x^2)) between the limits of x = 1 and x = 2 (AQA core 3 maths


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences