Solve the simultaneous equations: 4x+5y=13 and 3x-2y=27


Equation 1 is 4x+5y=13 - multiply it by 3, Equation 2 is 3x-2y=27 - multiply it by 4, New equation 1 is 12x+15y=39, New equation 2 is 12x-8y=108, Subtract new equation 2 from new equation 1 - 23y=-69 therefore y=-3, Substitute y=-3 into equation 1 - 4x+(5x-3)=13, 4x-15=13, 4x=28, x=7. Final answer: x=7, y=-3

TD
Answered by Thea D. Maths tutor

4432 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Express 56 as a product of prime factors in its simplest form


At a football game number of men : number of women : number of children = 13 : 5 : 7 There are 4152 more men than women. Work out the number of children at the game.


Factorise x² + 2x - 8


How do I solve simultaneous equations?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning