Solve the simultaneous equations: 4x+5y=13 and 3x-2y=27


Equation 1 is 4x+5y=13 - multiply it by 3, Equation 2 is 3x-2y=27 - multiply it by 4, New equation 1 is 12x+15y=39, New equation 2 is 12x-8y=108, Subtract new equation 2 from new equation 1 - 23y=-69 therefore y=-3, Substitute y=-3 into equation 1 - 4x+(5x-3)=13, 4x-15=13, 4x=28, x=7. Final answer: x=7, y=-3

TD
Answered by Thea D. Maths tutor

4448 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following simultaneous equations: 3x + y = 11, 2x + y = 8


(6/x-2)-(2/x+3)=1


Jenny has 3 stacks of coins - A B and C. Altogether the coins equal £1.30. Stack B has 3 times as much money has Stack A. Stack C has 2 times as much money as Stack B. How much money is in Pile C?


A shop trying to sell a laptop reduces its price by 7% at the very end of each week, from an initial price of £600. If you have £365 to spend, how many weeks must you wait until you can buy the laptop?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning