Given that the increase in the volume of a cube is given by dV/dt = t^3 + 5 (cm^3/s). The volume of the cube is initially at 5 cm^3. Find the volume of the cube at time t = 4.
- Identify that this is a rate of change question and set up the boundary conditions of V = 5 when t = 02) Take the dt to the right side and explain to integrate both sides of the equation to 'sum over all the tiny bits of time and tiny bits of V'3) Plug in the boundary conditions as a constant will drop out, and finally put t=4 into the formula. Write answer WITH UNITS.
TW
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