What is the empirical formula of a compound with the following composition by mass, 48.0g C, 4.0g H and 48.0g O?
There are 3 Steps to answering this question:But first you need to understand what is meant by empirical formula:The simplest whole number ratio of the atoms of each element present in a compound.1) First work out the number of moles of each element present:Do this by using Moles = Mass(g) / Relative Mass (g/mol) Moles Carbon = 48.0/12 = 4Moles Hydrogen = 4/1 = 4Moles Oxygen = 48/16 = 3 2) Write this number as a ratio and simplify if necessary:4:4:3, cannot be simplified3) Write this ratio as a formula:C4H4O3This is the answer.
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