Find the derivative of the following function: f(x) = x(x^3 + 2x)

f(x) becomes f'(x)1) First multiply out the brackets (by adding the indices) = x^4 + 2x^22) Then differentiate this. The indices moves to the front and multiplied by the number before the x. The indices is then decreased by 1.3) x^ 4 becomes 4x^34) 2x^2 becomes 4x^1... anything to the power of 1 is just itself so this becomes just 4x5) The final answer is f'(x) = 4x^3 + 4x

SS
Answered by Shamailla S. Maths tutor

2774 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A particle of mass m is placed on an slope with an incline 30 degrees. Once released it accelerates down the line of greatest slope at 2 m s^-2. What is the coefficient of friction between the particle and the slope?


What is differentiation?


Solving a quadratic with ax^2 e.g. 2x^2 - 11x + 12 = 0


Differentiate with respect to x: y=(6x^2-1)/2sqrt(x)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences