solve y=3x+4, x=y+1

Equation 1) y=3x+4Equation 2) y=x+1
Rearrange equation 2 into terms of x as this is the simplest: x= y-1 (We do this by subtracting 1 off of each side to get X by itself)Substitute new equation 2 into 1: y=3(y-1)+4Expand the bracket by separately multiplying the factors inside the bracket by the value in front: y=3y-3+4Collect like terms: -1=2y (we do this by collecting the y's on the side where they will be positive and the single numbers on the other side and add together)Now we can solve y=-1/2 (we do this by dividing each side by 2 to get y on its own)Now we can substitute this value back into equation 2 to get: -1/2=x+1Subtract 1 off of each side to get -3/2 = x

CS

Related Maths GCSE answers

All answers ▸

How do I multiply indices together?


Factorise 8x^2 + 6x +1


How would you solve the simultaneous equations y=x+1 and y=4x-2


Find the length of a side of the triangle (Pythagoras' Theorem) Two sides are of length 3cm and 4cm, find the length of the Hypotenuse.