Find the stationary points of the equation. f(x)=3x^2+4x.
Stationary points are points on the graph where the gradient is equal to 0.The gradient for any given point can be calculated by differentiating the original equation.f(x)=3x^2+4xDifferentiating gives:=> f’(x)=6x+4Stationary points are where f’(x)=0=>6x+4=0=> 6x=-4=>x=-2/3To find y value input the x value into the original equation.f(-2/3)=3(-2/3)^2+4(-2/3)=> 4/3-8/3=> -4/3Answer: stationary point is at (-2/3,-4/3)
EW
Related Maths A Level answers
All answers ▸For the curve y = 2x^2+4x+5, find the co-ordinates of the stationary point and determine whether it is a minimum or maximum point.
Solve the equation d/dx((x^3 + 3x^2)ln(x)) = 2x^2 + 5x, leaving your answer as an exact value of x. [6 marks]
Differentiate f(x)= x^3 + x^(1/3)-2
complete the square of x^2 + 2x - 6