Find the stationary points of the equation. f(x)=3x^2+4x.

Stationary points are points on the graph where the gradient is equal to 0.The gradient for any given point can be calculated by differentiating the original equation.f(x)=3x^2+4xDifferentiating gives:=> f’(x)=6x+4Stationary points are where f’(x)=0=>6x+4=0=> 6x=-4=>x=-2/3To find y value input the x value into the original equation.f(-2/3)=3(-2/3)^2+4(-2/3)=> 4/3-8/3=> -4/3Answer: stationary point is at (-2/3,-4/3)

EW
Answered by Ethan W. Maths tutor

4065 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How to find the reciprocal of a graph, such as y=cos(x)?


y = x^x, find y'


I don't understand differentiation. How does it work?


Find dy/dx of 5x^2 + 2y^3 +8 =17.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences