Find the stationary points of the equation. f(x)=3x^2+4x.

Stationary points are points on the graph where the gradient is equal to 0.The gradient for any given point can be calculated by differentiating the original equation.f(x)=3x^2+4xDifferentiating gives:=> f’(x)=6x+4Stationary points are where f’(x)=0=>6x+4=0=> 6x=-4=>x=-2/3To find y value input the x value into the original equation.f(-2/3)=3(-2/3)^2+4(-2/3)=> 4/3-8/3=> -4/3Answer: stationary point is at (-2/3,-4/3)