Differentiate (x^2)*(e^x) using product rule
Product rule: d/dx[f(x)g(x)]= f(x)d/dx[g(x)] + g(x)d/dx[f(x)]Let f(x)=x^2 and g(x)=e^xf'(x) = 2x and g'(x) = e^x Therefore,The derivative of (x^2)(e^x) = 2x(e^x) +(x^2)(e^x)
JB
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