Prove that f(x) the inverse function of g(x) where f(x)= - 3x–6 and g(x)= - x/3–2

f(x) and g(x) are inverse functions when the following equations are true:f(g(x))=x
g(f(x))=xTo find (f(g)(x)) or (g(f(x)), use the inner function as the input for the outer function.
f(g(x))=-3((-x/3-2))-6 = x
g(f(x))= (-(-3x-6)/3)-2 = x, hence  f and g are inverse functions


SK
Answered by Sheela K. Maths tutor

3424 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you intergrate basic algebra?


Integrate this funtion f'(x)=2x +4 with respect to x (C1 integration)


(19x - 2)/((5 - x)(1 + 6x)) can be expressed as A/(5-x) + B/(1+6x) where A and B are integers. Find A and B


Given y = 3x^(1/2) - 6x + 4, x > 0. 1) Find the integral of y with respect to x, simplifying each term. 2) Differentiate the equation for y with respect to x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning