Solve x^2 = 4(x – 3)^2

x2 = 4(x-3)2x2 = 4(x-3)(x-3) - showing that these are double bracketsx2 = 4(x2 - 6x + 9) - expanding the double bracketsx2 = 4x2 - 24x + 36 - multiplying the 4 by the expression inside to remove the brackets0 = 3x2 - 24x + 36 - rearrange to make the equation equal to 00 = x2 - 8x + 12 - realise that there is a common factor of 3 so divide by 3 to simplify the equation0 = (x-6)(x-2) - factorise the expression by finding two numbers that add to (-8) and multiply to make (+12).Finally solve each bracket separately by making them equal to 0 and rearranging for x. x - 6 = 0 so x = 6or x - 2 = 0 so x = 2

EL
Answered by Emily L. Maths tutor

3700 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

You are given a triangle ABC with sides length AB = 20cm, BC = 100cm and angle A = 70 degrees. Find the angle of C in degrees.


A cuboid has sides such that the longest side is two units more than the shortest side, and the middle length side is one unit longer than the shortest side. The total surface area of the cuboid is 52 units². What is the length of the shortest side?


How can I prove that an angle in a semi-circle is always 90 degrees?


If 5x + 3y = 27 and 6x - 2y = 10, find x and y


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning