How do you multiply out brackets
This is simple as long as you remember FOIL:
First
Outside
Inside
Last
So, for example, let's multiply out (2x+1)(4x-3)
Multiply the first number from each bracket together: 2x times 4x = 8x2
Then the outside from each bracket: 2x times -3 = -6x
Then inside: 1 times 4x = 4x
And outside: 1 times -3 = -3
Then add all these together: 8x2 -6x +4x-3
Final answer: 8x2 -2x -3
HM
Related Maths GCSE answers
All answers ▸Solve the following simultaneous equations: x^2 + y^2 = 12, x - 2y = 3
What is meant by 'the degree of a polynomial'?
Solve the simultaneous equation by elimination: 3x + y = 11 and 5x + y = 4
f(x) = x^2 + 4x − 6 f(x) can be written in the form (x + m)^2 + n. Find the value of m and the value of n.