How do you integrate by parts?

This is one of the trickier methods of integration, and it requires some practise. The basic idea is to split a function which would be difficult to integrate into two parts. Differentiating one part and integrating the other will then lead to a function which is much easier to integrate.

The formula is that the integral of u dv = uv - the integral of v du. It is best demonstrated with an example:

Let's integrate f(x) = xcos(x)

We can see that x will disppear if we differentiate it, so let's set x = u and cos(x) = dv.

Differentiating u and integrating dv then gives du = 1 and v = sin(x)

Now we substitute these into the formula: xsin(x) - integral of sin(x)

Sin(x) is easy to integrate, it is just -cos(x). Now we have our answer! The integral of xcos(x) = xsin(x) + cos(x) + c, where c is our unknown (and always necessary!) constant of integration.

HM

Related Maths A Level answers

All answers ▸

Using answer to previous question state the coordinates of the minimum


Solve the following equation: x^(3) - 6x^(2) + 11x - 6 = 0


The complex conjugate of 2-3i is also a root of z^3+pz^2+qz-13p=0. Find a quadratic factor of z^3+pz^2+qz-13p=0 with real coefficients and thus find the real root of the equation.


Differentiate: y = xsin(x)