Differentiate y=x/sin(x)

This equation has one function of x divided by another function of x, we therefore have to use the quotient rule and is written in the form f(x)/g(x). 

The quotient rule is therefore

f'(x)g(x)-g'(x)f(x)/g2(x)

The first step would be to differentiate f(x) and g(x). 

f'(x)=1 g'(x)=cos(x)

The numerator of this fraction would therefore be 

1*sin(x)-xcos(x) =sin(x)-xcos(x)

To calculate the denominator you simply square g(x)

g2(x)= sin2(x)

So the answer would be sin(x)-xcos(x)/sin2(x)

RF

Related Maths A Level answers

All answers ▸

find dy/dx of the equation y=ln(x)2x^2


How do you find the point of intersection of two vector lines?


How come x^2 = 25 has 2 solutions but x=root(25) only has one? Aren't they the same thing?


The equation of curve C is 3x^2 + xy + y^2 - 4x - 6y + 7 = 0. Use implicit differentiation to find dy/dx in terms of x and y.