Answers>Maths>GCSE>Article

Solve( 3x−2)/4 −(2x+5)/3= (1−x )/6

Firstly, take a common denominator for the left hand-side of the equation which would be 12 and then carrying out the subtraction. After carrying out the subtraction you will be left with two fractions - one on each side of the equation. Subsequently you do cross multiplication and find the value of x from the linear equation which would be 28/3.
3(3x-2)- 4(2x+5)= 2(1-x)9x-6-8x-20=2-2xx+2x=26+23x=28x=28/3 or 9 1/3

Answered by Wahid R. • Maths tutor

5280 Views

See similar Maths GCSE tutors

Solve( 3x−2)/4 −(2x+5)/3= (1−x )/6

Related Maths GCSE answers

Find the nth term of the sequence 7,11,15,19...

How do I solve the equation x^2 + 6 = -5x

A cylinder has dimensions: diameter = 4x+2 and height = 4. Work out the volume of this cylinder. Give your answer in terms of x

Solve ((3x-2)/4) - ((2x+5)/3) = ((1-x)/6)