How do I expand (x - 4)(2x + 3y)^2 ?

To start off, to make things clearer we can write the expression as:(x - 4)(2x + 3y)(2x + 3y)Now focus on just two of the brackets, say (2x + 3y)(2x + 3y). To expand this, we need to do the following four multiplications: the first term in the first bracket (2x) with the first term in the second bracket (2x) to get 4x^2, the first term in the first bracket (2x) with the second term in the second bracket (3y) to get 6xy, the second term in the first bracket (3y) with the first term in the second bracket (2x) to get 6xy and finally the second term in the first bracket (3y) with the second term in the second bracket (3y) to get 9y^2. The expansion of the expression is then the sum of all these terms: 4x^2 + 6xy + 6xy + 9y^2. We can simplify this immediately to get: (2x + 3y)(2x + 3y) = 4x^2 + 12xy + 9y^2.This means we now want to expand: (x - 4)(4x^2 + 12xy + 9y^2). We use the same technique as before, that is, to multiply each term in the first bracket with each term in the second bracket, then take the sum of these. Thus, we find the answer: 4x^3 + 12x^2y + 9xy^2 - 16x^2 - 48xy - 36y^2.

HM
Answered by Hector M. Maths tutor

5371 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A bottle contains 300ml of medicine, the dose for a child can be given by (m*a)/150 where m is the child's age in months and a is the adult dosage of 40ml. If you need 2 doses a day, how long will the medicine last until it's empty for a 2y/o child?


The equation 5x^2 + px + q = 0, where p and q are constants, has roots t and t+4. Show that p^2 = 20q + 400.


Robin and Emma both buy cupcakes for a bake sale. Between them, they purchase 125 cupcakes for the bake sale. Emma buys 50% more cupcakes then Robin and gets a 20% discount. The total cost of the 125 cupcakes was £137.5. What is the price of one cupcake?


blah blah blah


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning